Michaela runs to the end of her street and back in 90 s. Her brother, Jacob, walks to the end of the street and back in 3 min. They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob. How many times did each person go to the end of the street and back?

Given :

Michaela runs to the end of her street and back in 90 s.

Her brother, Jacob, walks to the end of the street and back in 3 min.

They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.

To Find :

How many times did each person go to the end of the street and back.

Solution :

Let, they both walk for T seconds.

Number of rounds Michaela walk is, n₁ = T/90 .

Number of rounds Jacob walk is, n₂ =T/180 .

It is given that :

n₁ = n₂ + 5

T/90 + T/180 = 5

( T/90 + T/180 ) × 180 = 5×180

2T + T = 900

3T = 900

T = 300 s

So, n₁ = 300/90 = 3

n₂ = 1

Hence, this is the required solution.

easy math just plug in a and b

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6