What is the turning point of the quadratic function y=1/2(x+10)^2)-6

The coordinates of the turning point will be:

The graph is also attached.

Step-by-step explanation:

Given the expression

simplifying

We know that the quadratic equation generally represents Parabola. We know that a turning point of the parabola of the quadratic equation depends upon the direction of the Parabola and the value of the leading coefficient.

The point, where the parabola tends to change the direction, is called the 'vertex'.

In other words, the vertex of the quadratic Parabola represents the turning point of the quadratic function.

Given the expression

Parabola params are:

a = 1/2, b = 10, c = 44

As the leading coefficient = 1/2 which is less than 1, thus it represents the up-down facing Parabola.

Thus, the x-coordinate of the vertex:

x = -b/2a

putting x = -10 in the original equation

Therefore, the coordinates of the turning point will be:

The graph is also attached.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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