11. The weight of large bags of one brand of potato chips is a random variable with a mean of 18 ounces and a standard deviation of 0.7 ounces. The amount of chips a professional caterer pours into a certain size of serving bowl can be described as a random variable with a mean of 4 ounces and a standard deviation of 0.3 ounces. The mean amount left in the bag after the caterer has filled two bowls is 10 ounces. Assuming these two variables are independent, what is the standard deviation of this remaining weight

The standard deviation of this remaining weight is 0.56.

Step-by-step explanation:

The information provided is:

For independent random variables the variance of the sum is the sum of the individual variances.

Compute the standard deviation of this remaining weight as follows:

Thus, the standard deviation of this remaining weight is 0.56.

is there any photos or whatever?

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week