When a baseball is hit by a batter, the height of the ball, h(t), at time t, , is determined by the equation If t is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?

t ≤ 1

Step-by-step explanation:

Complete question:

When a baseball is hit by a batter, the height of the ball, h(t), at time t, t=0 is determined by the equation h(t)=-16t^2+64t^2+4. If t is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?

If the height of the ball is greater than or equal to 52, the equation becomes;

h(t)=-16t^2+64t^2+4

-16t^2+64t^2+4≥ 48

-16t²+64t + 4 - 52≥0

16t²-64t² +48≥0

-48t²+48≥0

Subtract 48 from both sides

-48t²+48-48≥0-48

-48t²≥-48

t²≤-48/-48

t²≤ 1

t ≤ 1

Hence the required interval is t ≤ 1

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137