Use the inermediate value Theorem to choose an interval over which the function f(x)=-2x^3-3x+5, is guaranteed to have a zero. 1. [-3,-2]
2. [-2,0]
3. [0,2]
4. [2,4]

Choice 3: [0, 2]

Step-by-step explanation:

The Intermediate Value Theorem states that if we have a continuous function f over the interval [a, b] and k is a number between f(a) and f(b), then there must at least one point c within [a, b] such that f(c)=k.

Then, by the IVT, if the endpoints differ in signs, then we must have a zero within the interval since f must cross the x-axis in order to change signs.

So, we will test the endpoint values for each interval.

We have the function:

Choice 1:

Testing for the endpoints, we get:

And:

Since both values are positive, we are not guaranteed a zero for the interval [-3, -2].

Choice 2:

Testing endpoints, we get:

Again, both values are positive, so we are not guaranteed a zero.

Choice 3:

We get:

Since the values are of different signs, by the IVT, we are guaranteed a zero by for the interval [0, 2] since the function must cross the x-axis in order to become negative.

So, Choice 3 is correct.

Choice 4:

We get:

Both values are negative, so we are not guaranteed a zero.

Note: We may have a zero for the other three intervals. For instance, for [-3, -2], maybe we went from positive to negative to positive again all within the interval [-3, -2]. However, the only interval that guarantees a zero will be C.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

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