![\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](/tpl/images/1005/1706/a2a0e.png)
![\frac{d}{dx} [\frac{f(x)}{h(x)} ] \ at \ x = -2\\h(x) = x^3\\f(-2) = 8\\f'(-2) = 4](/tpl/images/1005/1706/b8fe1.png)
![\frac{d}{dx} [\frac{f(x)}{h(x)} ] = \frac{f'(x)h(x) - f(x)h'(x)}{h(x)^2}](/tpl/images/1005/1706/971d6.png)
Differentiate h(x) [Basic Power]: h'(x) = 3x²![\frac{f'(x)x^3 + f(x)[3x^2]}{(x^3)^2}](/tpl/images/1005/1706/94aa3.png)
Substitute in variables: 
Substitute in variables: ![\frac{4(-2)^3 - 8[3(-2)^2]}{[(-2)^3]^2}](/tpl/images/1005/1706/30d3f.png)
Evaluate: -2• Let f be a function such that f(-2) = 8 and f'(-2) = 4.
• Let h be the function h(x) = x3.
...
Mathematics, 22.12.2020 06:40 k123loveme
• Let f be a function such that f(-2) = 8 and f'(-2) = 4.
• Let h be the function h(x) = x3.
Evaluate
d f(x)
dx h(x)
at x = -2.
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Answers: 1
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