a, b, and c represent three different digits. If you add up all of the six two - digit numbers that can be written with these digits, where you don't use the same digit twice in each number, then the sum will be 528. Find these digits.

The answer is 7, 8 and 9. The Two-digit numbers are: ab, ac, ba, bc, ca, cb

The Sum of them is: 10a + b + 10a + c + 10b + a + 10b + c + 10c + a + 10c + b = 528

22a + 22b + 22c = 528

a + b + c = 528/22

a + b + c = 24      The only option of three different digits with the sum of 24 is 7, 8 and 9.

Hope this helps, stay safe, and merry christmas!

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.