If sin0=4/5, then cos0 =

If sin(theta) = 4/5, what is the value of cos(theta) in quadrant 1?

sin^2(theta) + cos^2(theta) = 1

(4/5)^2 + cos^2(theta) = 1

16/25 + cos^2(theta) = 1

cos^2(theta) = 1 - 16/25

cos^2(theta) = 25/25 - 16/25

cos^2(theta) = (25 - 16)25

cos^2(theta) = 9/25

cos(theta) = sqrt(9/25) ... we are in quadrant I, so cos(theta) > 0

cos(theta) = 3/5

Step-by-step explanation:

Hope it is helpful...

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!