Solve the rational equation x over 4 equals x squared over quantity 3 times x plus 3 and check for extraneous solutions. x = 1; x = 0 is an extraneous solution
x = 0; x = −1 is an extraneous solution
x = 0 and x = 1
x = 0 and x = −1

Last one and the bottom answer choice is y=(x-4)^2+1 you guys!

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

Scores on a university exam are normally distributed with a mean of 78 and a standard deviation of 8. the professor teaching the class declares that a score of 70 or higher is required for a grade of at least “c.” using the 68-95-99.7 rule, what percentage of students failed to earn a grade of at least “c”?