During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit. Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

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  40.5 ft

Step-by-step explanation:

Solve for the time at which the balls meet, then find the corresponding height.

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The balls will meet at the height such that the two values of h are the same.

  -16t^2 +56t = h = -16t^2 +156t -248

  0 = 100t -248

  t = 2.48

Using the first equation to find h, we have ...

  h = t(-16t +56) = 2.48(-16·2.48 +56) = 40.4736

The balls meet at a height of about 40.5 feet.

Use substitution to write the equation: -16t^2 +56t = -16t^2 + 156 - 248

simplify and solve for t, which is 2.48 seconds

substitute 2.48 for t into either equation to get h=40.5 feet

is it 35

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

step-by-step explanation: