A food manufacturer uses an extruder (a machine that produces bite-size cookies and snack food) that yields revenue for the firm at a rate of $200 per hour when in operation. However, the extruder breaks down an average of two times every day it operates. If Y denotes the number of breakdowns per day, and suppose Y follows a Poisson distribution. The daily revenue generated by the machine is R=1600−50Y^2. Find the expected daily revenue for the extruder.

$1300

Step-by-step explanation:

λ = average = 2 per day, Y denotes the number of breakdowns per day,

But E(Y) = λ, E[Y(Y - 1)] = λ²

E(Y²) = E[Y(Y - 1)] + E(Y), hence:

E(Y²) = λ² + λ

The daily revenue is R=1600−50Y². The expected daily revenue for the extruder E(R) is:

E(R) = E(1600−50Y²) = 1600 - 50E(Y²)

E(R) = 1600 - 50(λ² + λ)

Substituting:

E(R) = 1600 - 50(2² + 2)

E(R) = 1600 - 300 = 1300

E(R) = $1300

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.