The formula for the lateral area of a right cone is LA = rs, where r is the radius of the base and s is the slant height of the cone. Which are equivalent equations? Select two correct answers. s = s equals StartFraction L A Over pi r EndFraction. s = s equals StartFraction pi r Over L A EndFraction. s = LAr r = r equals StartFraction L A Over pi s EndFraction. r = LAs

Complete Question

The formula for the lateral area of a right cone is LA = πrs, where r is the radius of the base and s is the slant height of the cone. Which are equivalent equations? Select two correct answers.

a) s = s equals StartFraction L A Over pi r EndFraction.

b) s = s equals StartFraction pi r Over L A EndFraction.

c) s = LAr

d) r = r equals StartFraction L A Over pi s EndFraction.

e) r = LAs

a) s equals StartFraction L A Over pi r EndFraction.

d) r = r equals StartFraction L A Over pi s EndFraction.

Step-by-step explanation:

The formula for the Lateral Surface Area of a right cone is given in the question as:

LA = πrs

Where

r is the radius of the base and s is the slant height of the cone.

From the options given,

We can make s the subject of the formula.

Hence:

Making s the subject of the formula

LA = πrs

Divide both sides by πr

s = LA/πr

Hence: Option a) s equals StartFraction L A Over pi r EndFraction. Is correct.

Step 2

Making r the subject of the Formula

LA = πrs

Divide both sides by πs

r = LA/πs

Hence: Option d) r equals StartFraction L A Over pi s EndFraction. Is correct.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option