Find the equation, in standard form, of the quadratic function that has x-int
and passes through point (-3,8)

−6√7

Step-by-step explanation:

−3√28-328

Rewrite 2828 as 22⋅722⋅7.

Factor 44 out of 2828.

−3√4(7)-34(7)

Rewrite 44 as 2222.

−3√22⋅7-322⋅7

Pull terms out from under the radical.

−3(2√7)-3(27)

Multiply 22 by −3-3.

−6√7-67

Exact Form:

−6√7

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

i think it’s a i believe