Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0). If D is the midpoint of BC, the the length (distance) of AD.
write the midpoint
write the distance

Point D:

d = √41

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Pre-Calculus

Midpoint Formula [3D]: Distance Formula [3D]:

Step-by-step explanation:

Step 1: Define

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

Step 2: Find Point D

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

Substitute [MF]:                    Add/Subtract:                       Divide:                                  

Step 3: Find distance d

Simply plug in the 2 coordinates A and D into the distance formula to find distance d

Substitute [DF]:                    Subtract/Add:                       Exponents:                           Add:                                      

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12