Hello, how to do 12(c) ?:)

Step-by-step explanation:

27^x / sqrt(9^y) = 3 and log2(x) - 2 = log2(y).

3^3x / 3^y = 3 and log2(x) - log2(4) = log2(y).

3x - y = 1 and x/4 = y.

Therefore x = 4/11 and y = 1/11.

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Step-by-step explanation:

27 = 3³ and √9 = 3 and xy ≠ 0

= 3 ⇔ = ⇒ 3x - y = 1

- 2 = ⇔ - = 2 ⇔ = 2 ⇒ = 2² ⇒ x = 4y

3(4y) - y = 1 ⇒ y = and x =

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step-by-step explanation: