in how many ways the letter of the word STRANCE be arranged so that the vowels occupy only the odd place

1440

Step-by-step explanation:

We're given the word ‘STRANCE’ STRANCE happens to be a 7 letterered word. It contains just 2 vowels A and E, with 5 consonants S, T, R, N and C. We're told to arrange in a way that the vowels occupy only the odd places, so in the word, there exist 4 odd places. The 1st, 3rd, 5th and 7th spot.

The two vowels can be arranged in 4P2 ways. This means that the remaining 5 consonants can be arranged among themselves in a 5P5 ways. Using the permutation formula, we know that

P (n, r) = n!/(n – r)!, so

P (4, 2) * P (5, 5) =

4!/(4 – 2)! * 5!/(5 – 5)! =

4!/2! * 5! =

(4 * 3 * 2!)/2! * 5! =

(12 * 2!)/2! * 120 =

(12 * 2)/2 * 120 =

12 * 120 = 1440

the function makes a strait line horizontally with no x intercept but a y intercept at 9.

the answer will be b x² +x-1

step-by-step explanation: