In the given figures find x and y

1) x = 40° & y = 50°

2) x = 100° & y = 80°

Step-by-step explanation:

1)

ABCD is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are touching on the circle). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.

⇒ ∠ADC + ∠ABC = 180°

⇒ 130° + y = 180°

⇒ y = 180 - 130 = 50°

In ΔABC ,

∠ACB = 90° (∵ AB is the diameter of the circle and a diameter subtends an angle of 90° on any point on circle.)

Using angle sum property of triangle ,

∠ABC + ∠ACB + ∠CAB = 180°

⇒ y + 90° + x = 180°

⇒ x + 50° + 90° = 180°

⇒ x + 140° = 180°

⇒ x = 180 - 140 = 40°

2)

ΔABC is an isosceles triangle (∵AB = AC). As it is an isosceles triangle , it's base angles will be equal. So , ∠ABC = ∠ACB = 50°

Using angle sum property of triangle ,

∠ABC + ∠ACB + ∠BAC = 180°

⇒ 50° + 50° + y = 180°

⇒ y + 100° = 180°

⇒ y = 180 - 100 = 80°

ABEC is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are on the circle.). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.

⇒ ∠BAC + ∠BEC = 180°

⇒ y + x = 180°

⇒ x + 80° = 180°

⇒ x = 180 - 80 = 100°

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068