In a random sample of microwave ovens, the mean repair cost was $ and the standard deviation was $. Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, assume the population is normally distributed, find the margin of error and construct a % confidence interval for the population mean μ. A 98% confidence interval using the t-distribution was (687,913). Compare the results. The margin of error of μ is:

Complete Question

In a random sample of 13 microwave ovens, the mean repair cost was $90.00 and the standard deviation was $15.20. Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, assume the population is normally distributed, find the margin of error and construct a 98% confidence interval for the population mean u. A 98% confidence interval using the t-distribution was (78.7,101.3). Compare the results. The margin of error of u is

The value  is  

Step-by-step explanation:

From the question we are told that

    The sample is  

     The sample mean is  

     The standard deviation is  

      The  lower limit of the  98% confidence interval is

      The  upper  limit of the  98% confidence interval is

Generally the margin of error is mathematically represented as

=>    

=>    

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.