6. The total age of three siblings; Aku, Afi and Nortey is 28 years. Aku's age is twice Nortey's
age
whiles Afi's age is four more than
Nortey's age. If they are to share an amount of
$1,400 in the ratio of their ages, find:
(i) the actual age of the children;
(ii) how much each person received?

Aku's age=2×28=56

Afi's age=4×28=112

Ratio of their ages=28:56:112

Nortey had=28/196

Step-by-step explanation:

Step-by-step explanation:

Givens

Aku = ak

afi = af1

nortey:=no

ak = 2*no

af1 = no + 4

Equation

af1 + ak + no = 28

Solution

no+4 + 2no + no = 28

4no + 4 = 28

4n = 28 - 4

4n = 24

no = 24/4

Answer Part i

no = 6

af1 = no + 4 = 10

ak = 2*6 = 12

Answer Part (ii)

6x + 10x + 12x = 1400

28x = 1400

x = 50

No = 6* 50 = 300

Af1 = 10*50 = 500

Ak = 12*50 = 600

more detail

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !