Please find the perimeter and the area of the figure below.

Total Composite Area: 5/2π in²

Total Composite Perimeter: 3π + 2 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Geometry

Step-by-step explanation:

Step 1: Define

Radius of Circle ABC = 2 in

Radius of Circle AD = 1 in

Step 2: Find Area

Since the formulas are for use for full circles and we only have semicircles, we need to half the formulas.

We add the 2 composite figures to find the total area.

Step 3: Find Perimeter

Since the formulas are for use for full circles and we only have semicircles, we need to half the formulas.

We add the 2 composite figures to find the total perimeter. Don't forget circumference is only the curve of the circle.

Hello!

Area:

Perimeter:

We can divide the figure into two semicircles:

One semicircle of radius 2 inch (Arc ABC) and another semicircle of radius 1 inch (Arc AD)

Find the area using the formula for the area of a semicircle:

A = 1/2(πr²)

Find the area for each semicircle:

Arc ABC:

A = 1/2π(2²)

A = 1/2(4π)

A = 2π

Find the area of semicircle AD:

A = 1/2π(1²)

A = 1/2π(1)

A = 1/2π

Add the two areas together:

1/2π + 2π = 5/2π inches squared.

Perimeter:

Use the formula for the circumference of a semicircle:

C = 1/2(2rπ)

Use the equation to solve for the perimeter of each semicircle.

Semicircle ABC:

C = 1/2(2(2)(π))

C = 2π inch

Semicircle AD:

C = 1/2(2(1)(π))

C = 1π inch

There is also a 2 inch segment that must be incorporated, so the total perimeter is:

2π + 1π + 2 = 3π + 2 inches.

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step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)