What is the function written in vertex form? O f(x) = 5(x + 4) - 80
O fx) = 5(x + 8) - 80
O f(x)=5(x + 4)80
O f(X) = 5(x+ 8)²80

Step-by-step explanation:

f(x) = 5x^2 + 40x                  Take out the common factor of 5

f(x) = 5(x^2 + 8x )                 Put 1/2 8  squared inside the brackets.

f(x) = 5(x^2 + 8x + 16)           x^2 + 8x + 16 is a perfect square

f(x) = 5(x + 4)^2                  

Here's the tricky part. What you have actually added inside the brackets is 5 * 16 which is equal to 80. You must then subtract 80 outside the brackets.

f(x) = 5(x + 4)^2 - 80. The closest answer appears to be C or maybe A which  ever one is closest to my answer.            

based on context clues you gave i'm assuming the answer would be c.

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y