Calculate the Compound interest for 18,000 for 2 years at 8% per annum compounded annually.

AGAIN URGENT
THANK U

Step-by-step explanation:

principal = 18000

Time = 3 yrs

Rate. = 8%.

CI. = ?

Now

CI = p ( 1+ R÷ 100) ^T

CI = 18000( 1+ 8÷ 100 ) ^ 2

CI = 20995.2

Hope it's is Right :-)

interest ( I ) , principal ( P ), Time ( T ) , Rate ( R )

P = I×T×R

100

P = 18,000×2×8

100

= 18,000×16

100

so two zero cancel other two zero living

= 180×16 = 180 × 16

1

= 180 × 16

P = 2880

1

we fixe in the values

answer: it is 1: 47 pm

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0