.A and B together can do a piece of work in 6,2 upon 3 days, but B alone can do it in 10 days. How long will a take to do it alone

20 days

Step-by-step explanation:

Giveb that :

Days taken by A and B = 6 2/3 days

Days taken by B alone = 10 days

Number of days taken by A alone =?

Rate of B working Alone = 1/10

Let rate of A working alone = 1/x

1/10 + 1/x = rate working together

Rate working together = (1 ÷ 20/3)) = 3/20

Hence,

1/10 + 1/x = 3/20

1/x = 3/20 - 1/10

1/x = (3 - 2) / 20

1/x = 1 / 20

x = 20

x = 20

Hence, it will take A 20 days

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

im here

step-by-step explanation: