A man bought a cow and a horse for $500. He sold the cow at a profit of 10% and the horse at a loss of 10% and suffered a loss of 2% on the whole. What did he pay for the cow?

The man paid $200 for the cow

Step-by-step explanation:

System of Equations

Let's call:

x = price of the cow

y = price of the horse

The man bought the cow and the horse for $500, thus

x + y = 500        [1]

The cow was sold at a profit of 10%, thus:

Sale price of the cow= 1.1x

The horse was sold at a loss of 10%, thus:

Sale price of the horse= 0.9y

The total operation was a 2% loss, i.e. 0.98*500=490. Thus, we have:

1.1x + 0.9y = 490        [2]

From [1]:

y = 500 - x

Substituting in [2]:

1.1x + 0.9(500 - x) = 490

Operating:

1.1x + 450 - 0.9x = 490

0.2x = 490 - 450 = 40

x = 40/0.2

x = 200

The man paid $200 for the cow

angle addition postulate

2x=56

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.