Solve -4x² = 5x + 9. *a x=-1 or x=-1/4 x=-1 or x = 9/4 x= 2 or x= 3 No real solutions

No real solutions

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Algebra I

Standard Form: ax² + bx + c = 0Quadratic Formula:

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

-4x² = 5x + 9

Step 2: Rewrite

Find standard form.

Subtract 5x on both sides:                    -4x² - 5x = 9Subtract 9 on both sides:                      -4x² - 5x - 9 = 0

Step 3: Identify Variables

a = -4

b = -5

c = -9

Step 4: Solve for x

Substitute [QF]:                    Exponents:                           Multiply:                                Subtract:                               Factor:                                   Simplify:                                

Here we see that we get imaginary numbers.

∴ the quadratic would have no real roots.