Mathematics, 29.12.2020 14:00 ricky67
The portion of the parabola y²=4ax above the x-axis, where is form 0 to h is revolved about the x-axis. Show that the surface area generated is
A=8/3π√a[(h+a)³/²-a³/2]
Use the result to find the value of h if the parabola y²=36x when revolved about the x-axis is to have surface area 1000.
Answers: 3
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The portion of the parabola y²=4ax above the x-axis, where is form 0 to h is revolved about the x-ax...
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