find the amount and the compound interest on rupees 12000 at 6% p. a. compounded half yearly for 3/2 years

A= ₹3,112.72

CI = ₹1,112.72

Step-by-step explanation:

Here P = ₹ 12000

Since, interest is compounded half yearly.

Therefore, R = 6/2 = 3%

n = 3/2* 2 = 3 half years

CI = A - P

CI = 13,112.72 - 12000

CI = ₹1,112.72

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl