Tanr=061. Therefore, tan(90-A) ' = (All angle measurements are in degrees.) A. 1/tan(90-A)
B. 1/sin A
C. 1/cos(90-A)
D. 1/tan A

Find the equation using the point (4,8)

Solve the system of equations y= 3/2 - 1, -x+ y =-3

In right ∆abc shown below, the midpoint of hypotenuse ac is located at d and segment bd is drawn.if ab = 12 and bc = 16, then explain why bd = 10. hint: consider what you know about the diagonals of a rectangle.