The factors of 2x^2 + xy - 3y^2 are A (2x - 3y)(x + y)

B (2x + 3y)(x - y)

C (2x - y)(x + 3y)

D (2x + y)(x - 3y)

B. (2x + 3y)(x - y)

Step-by-step explanation:

              Write x y as a difference

   Factor out x from the equation

  Factor out 2x+3y from the expression

              <----- Answer

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !