In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and C are (2,5) and (-2,3). How do you find the possible pairs of coordinates of B?

The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively

The possible pairs of the coordinates of the point B are found as follows;

1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above

2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the  perpendicular intersection of the two newly constructed lines here

Step-by-step explanation:

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol