1) a) Factorize: G(x) = (x+5)2 – 3x(x+5). b) Solve G(x) = 0.
2) In the adjacent figure ABCD is a square:
a) Express the area of the square and the area
of triangle AEB in terms of x.
b) Calculate x so that the area of the square is equal
to 6 times the area of triangle AEB.

In bold.

Step-by-step explanation:

a.  (x+5)^2 – 3x(x+5)     x+5 is common

= (x + 5)(x + 5 - 3x)

= (x + 5)(5 - 2x)

b.  (x + 5)(5 - 2x) = 0

x = -5, 2.5.

2a.   Area of the square = (x + 5)^2

Area of triangle AEB

= 1/2 * base * height  

I am assuming that  H is the centre of AB , so

Area = x*x

= x^2.

2b

6x^2 = (x + 5)^2

6x^2 = x^2 + 10x + 25

5x^2 - 10x - 25 = 0

x^2 - 2x - 5 = 0

x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2

x = -1.45, 3.45.

 (we ignore the negative).

answer for #1 is c

answer for #2 is d

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e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)