Susan and Claire spend a certain amount of money from their money box each month to buy plants. The table shows the relationship between the amount of money (y) remaining in Susan's money box and the number of months (x): Number of Months
(x)

Amount Remaining (dollars)
(y)

1

50

2

45

3

40

4

35

The equation shows the relationship between the amount of money, y, remaining in Claire's money box and the number of months, x:

Function 2:
y = −6x + 50

Which statement explains which function shows a greater rate of change? (5 points)

Function 2 shows a greater rate of change because Claire spends $6 each month and Susan spends $5 each month.
Function 2 shows a greater rate of change because Claire spends $50 each month and Susan spends $15 each month.
Function 1 shows a greater rate of change because Susan spends $15 each month and Claire spends $44 each month.
Function 1 shows a greater rate of change because Susan spends $5 each month and Claire spends −$6 each month.

16 is the absolute value

step-by-step explanation:

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

ur right ive taken the test

step-by-step explanation: