If
f(x) = x?+ 2x- 4
and
g(x) - 3x+ 1
Find
g(f(3) = [? }+x +

F(x) = x^2 + 2x - 4

G(x) = 3x + 1

Find g(f(x))

- when it says g(f(x)), this means that you plug in the equation or value you were given for f(x) into EVERY x-value seen in the g(x) equation.

-in the g(x) equation (3x + 1) you were given ONE x-value.

So...

-you replace the x with the f(x) equation which is, x^2 + 2x - 4 (as shown below)

g(f(x)) = 3(x^2 + 2x - 4) + 1

• then distribute the 3 on the outside of the brackets with each number inside the bracket

= 3x^2 + 6x - 12 + 1

• add all the like terms up and you should get your final equation

= 3x^2 + 6x - 11 OR 3x^2 + 6x + (-11)

*Remember to always follow the BEDMAS or PEDMAS rule

I hope this helps. If you have any questions please let me know in the comment section.