A vanilla thickshake is $2 more than a fruit juice. If 3 vanilla thickshakes and 5 fruit juices cost $30, determine their individual prices using simultaneous elimination

vanilla thickshake = $5

fruit juice = $3

USING ELIMINATION METHOD

Let the price of vanilla thickshake = x

Let the price of fruit juice = y

Given that a vanilla thickshake is $2 more than a fruit juice.

so

Given that If 3 vanilla thickshakes and 5 fruit juices cost $30.

So the system of equations

Arrange equation variables for elimination

so

so the system of equations becomes

solve 8y = 24 for y

Divide both sides by 2

Divide both sides by 3

Therefore,

                                              2ND METHOD

Step-by-step explanation:

As a vanilla thickshake is $2 more than a fruit juice.

Given that 3 vanilla thickshakes and 5 fruit juices cost $30.

3(Vanilla thickshakes) + 5(fruit juice) = 30

3(x+2) + 5x = 30

3x+6+5x=30

8x+6=30

8x=30-6

8x=24

x = 3

Thus,

step-by-step explanation:

the answer to this is:

factor 2x2+16x+24

2x2+16x+24

=2(x+2)(x+6)

answer:

2(x+2)(x+6)

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