Carlos visita a sus abuelos cada 12 dias y su hermana sofia, cada8 dias. La ultima vez que conincidieron en la visita fue el dia 3 de enero ¿cuando volveran a coincidir? ¿cuantas veces habran visitado a sus abuelos cada uno entre los dos periodos que han coincidido?

Responder:

27 de enero

Horas de visita al abuelo antes de que coincida el horario = 1 vez

Horas de visita a Sofía antes de que coincida el horario = 2 veces

Explicación paso a paso:

Para obtener la hora en la que coincidirá su visita, obtenemos la L. C. M de 12 y 8

Abuelos (cada 12 días)

12:12, 24, 36, 48, 60, ...

Sofia (cada 8 días)

8: 8, 16, 24, 32, 40,

El mínimo común múltiplo de 12 y 8 es 24.

De ahí que su encuentro vuelva a coincidir a los 24 días.

3 de enero + 24 días = 27 de enero

Horas de visita al abuelo antes de que coincida el horario = 1 vez

Horas de visita a Sofía antes de que coincida el horario = 2 veces

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.