Mathematics, 02.01.2021 17:00 lizreed2002
During a certain24 -hour period, the temperature at time t (measured in hours from the start of the period) was T(t)=50+6t-1/3t^2 degrees. What was the average temperature during that period?
Answers: 2
![=\frac{1}{24}[50t+3t^2-\frac{1}{9}t^3]^{24}_{0}](/tpl/images/1010/9674/acaca.png)
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During a certain24 -hour period, the temperature at time t (measured in hours from the start of the...
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