If the mode of the data is 34.5, find the missing frequency 'f': Class
0-15
15 - 30
30 – 45
45 - 60
60 – 75
Frequency
2
7
f
3
7
please answer!

Given:

Frequency distribution table.

Mode = 34.5

To find:

The value of missing frequency 'f'.

Solution:

Formula for mode is

where, l is lower limit of modal class, is frequency of modal class, is frequency of preceding class, is frequency of succeeding class, h is class size.

Mode is 34.5, so the modal class is 30-45. So,

Putting these values in the above formula, we get

Divide both sides by 15.

Separating variable terms, we get

Divide both sides by -0.4.

Therefore, the value of f is 10.

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)