Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in slope intercept for (y=mx+b) with the values of m and b given as decimals, rounded to the nearest hundredth if necessary. y=20x;(2,2) The equation is y =
Please help very urgent! :)

y = - 0.05x - 1.9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

y = 20x ← is in slope- intercept form

with slope m = 20

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 0.05 , thus

y = - 0.05x + b ← is the partial equation

To find b substitute (2, - 2) into the partial equation

- 2 = - 0.1 + b ⇒ b = - 2 + 0.1 = - 1.9

y = - 0.05x - 1.9 ← equation of perpendicular line

answer: 177/8

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18