Which polynomial is factored completely? 121 x squared + 36 y squared
(4x + 4)(x + 1)
2 x (x squared minus 4)
3 x Superscript 4 Baseline minus 15 n cubed + 12 n squared

9514 1404 393

  a, d

Step-by-step explanation:

We assume you want factors that use real integers.

a) 121x² +36y² . . . . cannot be factored using real numbers

b) (4x +4)(x +1) = 4(x +1)²

c) x(x² -4) = x(x -2)(x +2)

d) x⁴ -15n³ +12n² . . . . cannot be factored*

* If the polynomial is n⁴ -15n³ +12n², then it factors as n²(n² -15n +12).

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

step-by-step explanation:

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