7. Slips are drawn form a box containing 100 slips written with numbers 1 to 100. If three slips are drawn one after the another with replacement, then the probability that first slip bears an even
number, second bears an odd number, third bears a perfect square number, is

a)1/100
b)1/25
c)1/45
d)1/40

D

Step-by-step explanation:

We need the numbers of each before we can calculate the probability

Number of even numbers are 50

Number of odd numbers are 50

Number of perfect squares;

1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 and 100

10 perfect squares

Probability of selecting even = probability of selecting odd = 50/100 = 1/2

Probability of selecting a perfect square = 10/100 = 1/10

Thus, the probability of having the draws in the other stated in the question will be;

1/2 * 1/2 * 1/10 = 1/40

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation: