A classroom is 11 m long, 8 m wide and 5.5 m high Find the sum of the areas of the four walls. ( please show the working out pleaseee)

209 m²

Step-by-step explanation:

The class room has a measurement of 11 m long, 8 m wide and 5.5 m high. Hence the walls of the classroom would be 4, with the following measurements.

Wall 1: 11 m by 5.5 m, Wall 2: 8 m by 5.5 m, Wall 3: 11 m by 5.5 m and Wall 4: 8 m by 5.5 m

The area of wall 1 = 11 m * 5.5 m = 60.5 m²

The area of wall 2 = 8 m * 5.5 m = 44 m²

The area of wall 3 = 11 m * 5.5 m = 60.5 m²

The area of wall 4 = 11 m * 5.5 m = 44 m²

The sum of areas of the fall wall = area of wall 1 + area of wall 2 + area of wall 3 + area of wall 4

The sum of areas of the fall wall = 60.5 + 44 + 60.5 + 44 = 209 m²

b is the answer that makes most sense

step-by-step explanation:

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315