1) Graph by making a
table.
y=1/2x+2

Below.

Step-by-step explanation:

You can use any 4 x values, so we could have:

- 2  0  2  4

Now find the corresponding y values by substitution in the equation:

For x = -2, y = 1/2 *-2 + 2 = 1.

For x = 0, y = 1/2 * 0 + 2 = 2.

For x = 2 , y = 1/2* 2 + 2 = 3.

For x =  4 , y = 1/2 * 4 + 2 = 4.

So the table is:

-2   0    2   4

1    2    3   4

You then plot the points (-2, 1), (0, 2), (2, 3) AND (4, 4) on the grid  and draw a line through them The graph will be a straight line.

∠cbe and ∠deb are same-side interior angles.

i took the test

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.