Help use the information above and the trigonometric identities to prove that Asin(wt+phi)=c2sin(wt)+c1cos(wt)

Answer and Step-by-step explanation:

Given Asin(wt + phi), we know that sin (A + B) = sinAcosB + sinBcosA. This means:

Asin(wt + phi) = Asin(wt)cos(phi) + Asin(phi)cos(wt).

Let Acos(phi) = c2 and Asin(phi) = c1 we have:

Asin(wt + phi) = c2sin(wt) + c1cos(wt)

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: