The focus of a parabola is (2,5) and the directrix is y=3. Find the equation of the parabola in standard form. A. Y= -x^2 /4 +x-5
B. Y= -x^2 /16 -x /8 -5 /4
C. Y= x^2 /4 -x+5
D. Y= x^2 /16 -x/4 +5/4

gaddgad

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

i dont know sorry

step-by-step explanation:

answer: -1

step-by-step explanation: