A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. Y=-16x^2+157x+104

The rocket will hit the ground approximately 10.77 seconds after launch.

Step-by-step explanation:

Let the height of the rocket as a function of time be represented by . According to the statement, we must solve the following equation:

(1)

The roots of the polynomial are calculated by the Quadratic Formula:

and

Since time is a positive variable, the only solution that is physically reasonable is:

The rocket will hit the ground approximately 10.77 seconds after launch.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17