What is the equation of the line that passes through the point (-5, -2) and has a
slope of -6/5

Step-by-step explanation:

you are given the slope m = -6/5 and one point (x1,y1) as (-5,-2)

next use  the point-slope formula [y-y1 = m(x-x1) ] and plug in the point and the slope

y-(-2) = -6/5(x-(-2))    ( they are making this tuff with all the minus signs :/ )

y+2 = -6/5(x+2)         ( nice looks better, distribute the -6/5 )

y + 2 = -6/5x -12/5    (move the 2 over )

y = -6/5x - 12/5 -2      ( 2 = 10/5 )

y = -6/5x -12/5 - 10/5    (add the fractions )

y = -6/5x -22/5    

that's in the form of the slope-intercept now  [ y = mx + b ] so you're done :)

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4