Write an equation in slope intercept form of the line that passes through (-2,10) and (1,1).

Step-by-step explanation:

1st use the two points to find the slope of the line that passes thru those two points

m = y2 - y1 / x2  - x1    

where point1 = ( x1, y1 )  and point2 = (x2, y2 )

your are given P1 = ( -2,10)  and P2 = (1,1)

find the slope

m = 1-(-2) / 1-10

m = 1+2 / -9

m = 3 / -9

m = - 1/3

then use the point-slope formula [y-y1 = m(x-x1)] with either of the two points, I'll use P2 b/c it seems easier (1,1) , you get the same results with either point and work the problem to the slope-intercept form [y = mx +b ]

y -y1 = m(x-x1)

y-1 = -1/3(x-1)

y-1 = -1/3x + 1/3

y = -1/3x + 1/3 + 1

y = -1/3x + 4/3

:)   got it ?

europa2433

europa2433

step-by-step explanation:

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true