Your class raised money by selling hot dogs and hamburgers. Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold for $1 (one dollar). The total money raised by your class was $80. Together you sold 108 hot dogs and hamburgers. How many of each were sold?

Number of hot dogs sold =  56

Number of  hamburgers sold = 52

Step-by-step explanation:

Let

Number of hot dogs sold = x

Number of  hamburgers sold = y

We can make equation from given equations:

(Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold for $1 (one dollar). The total money raised by your class was $80. )

 (Together you sold 108 hot dogs and hamburgers.)

Now we cam solve these system of equations to find value of x and y

Subtract both equations to get value of x:

We get value of x = 56

Now putting value of x in equation 2 to find value of y

So, we get y = 52

Therefore,

Number of hot dogs sold = x = 56

Number of  hamburgers sold = y = 52

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

x=6 and x=3

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