Recursive sequence. A sequence has f(1)=120, f(2)=60
-Help find the next 2 terms and what goes into the blank pls.

f(3)=0, f(4)=-60

f(n) = f(n-1) + (-60)

Step-by-step explanation:

Arithmetic Sequences

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

f(n)=f(1)+(n-1)r

Where

f(n) = nth term

f(1) = first term

r   = common difference

n  = number of the term

The given sequence has two known terms: 120, 60, ...

The common difference is found by subtracting consecutive terms:

r = 60 - 120 = -60

Thus the next two terms are:

f(3)=120+(3-1)(-60)=120-120 = 0

f(4)=120+(4-1)(-60)=120-180 = -60

Since each term is calculated as the previous term plus -60, then the recursive formula is:

f(n) = f(n-1) + (-60)

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

angle addition postulate

2x=56

step-by-step explanation: