(03.05 HC) In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to the fifth and final round. Steward scored 5 points in the first round. He then went on to score additional points in the second, third, and fourth rounds. In each of those rounds, his score was identical. Which inequality best shows the number of points, p, that Steward scored in each of the second, third, and fourth rounds if he earned a place in the finals? (1 point)

a
5 + 3p ≥ 30

b
5 + 3p ≤ 30

c
5p + 3 ≥ 30

d
5p + 3 ≤ 30

Given:

Score in first round = 5 points

Score in second, third and fourth rounds was identical.

A participant has to score a total of at least 30 points in the first four rounds combined to move on to the fifth and final round.

To find:

The inequality for the given problem.

Solution:

Let p be the number of points, p, that Steward scored in each of the second, third, and fourth rounds.

Score in first 4 rounds = Score of 1st round + Score of 2nd round + Score of  1s 3rd round + Score of 4th round

Score in first 4 rounds

A participant has to score a total of at least 30 points in the first four rounds combined to move on to the fifth and final round. It means the total score in first 4 rounds must be greater than or equal to 30.

Therefore, the correct option is A.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.